303 | AMA | February 2025

4829.797 - 4856.477 Sean Carroll

you could show that something, some feature of chemistry or solid state materials physics or something like that just doesn't work under these models. So I'm all in favor of doing that. It would be very, very hard to distinguish between Bohm and Everett on that account because Bohm and Everett have the same equation for the wave function. The wave function is just obeying the Schrodinger equation.